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Surface area and surface integrals. (Sect. 16.5) ◮ Review: Arc length and line integrals. ◮ Review: Double integral of a scalar function. ◮ Explicit, implicit, parametric equations of surfaces. ◮ The area of a surface in space. ◮ The surface is given in parametric form. ◮ The surface is given in explicit form. Review: Arc length and line integrals ◮ The integral of a function f : [a,b] → R is Z b n f (x)dx = lim Xf(x∗)∆x. n→∞ i a i=0 ◮ The arc length of a curve r : [t0,t1] → R3 in space is Z t 1 ′ st ,t = |r (t)|dt. 1 0 t 0 ◮ The integral of a function f : R3 → R along a curve Z Z t 1 ′ r : [t0, t1] → R3 is f ds = f r(t) |r (t)|dt. C t 0 ◮ The circulation of a function F : R3 → R3 along a curve Z Z t 1 ′ r : [t0, t1] → R3 is F·uds = F r(t) ·r (t)dt. C t 0 ◮ The flux of a function F : {z = 0}∩R3 → {z = 0}∩R3 along a loop r : [t0,t1] → {z = 0} ∩ R3 is F = I F · nds. C Surface area and surface integrals. (Sect. 16.5) ◮ Review: Arc length and line integrals. ◮ Review: Double integral of a scalar function. ◮ Explicit, implicit, parametric equations of surfaces. ◮ The area of a surface in space. ◮ The surface is given in parametric form. ◮ The surface is given in explicit form. Review: Double integral of a scalar function ◮ The double integral of a function f : R ⊂ R2 → R on a region R ⊂R2, which is the volume under the graph of f and above the z = 0 plane, and is given by ZZ n n f dA = lim XXf(x∗,y∗)∆x∆y. n→∞ i j R i=0 j=0 ◮ The area of a flat surface R ⊂ R2 is the particular case f = 1, that is, A(R) = ZZ dA. R Wewill show how to compute: ◮ The area of a non-flat surface in space. (Today.) ◮ The integral of a scalar function f on a surface is space. ◮ The flux of a vector-valued function F on a surface in space. Surface area and surface integrals. (Sect. 16.5) ◮ Review: Arc length and line integrals. ◮ Review: Double integral of a scalar function. ◮ Explicit, implicit, parametric equations of surfaces. ◮ The area of a surface in space. ◮ The surface is given in parametric form. ◮ The surface is given in explicit form. Explicit, implicit, parametric equations of surfaces Review: Curves on R2 can be defined in: ◮ Explicit form, y = f (x); ◮ Implicit form, F(x,y) = 0; ◮ Parametric form, r(t) = hx(t),y(t)i. The vector r′(t) = hx′(t),y′(t)i is tangent to the curve. Review: Surfaces in R3 can be defined in: ◮ Explicit form, z = f (x,y); ◮ Implicit form, F(x,y,z) = 0; ◮ Parametric form, r(u,v) = hx(u,v),y(u,v),z(u,v)i. Two vectors tangent to the surface are ∂ r(u,v) = h∂ x(u,v),∂ y(u,v),∂ z(u,v)i, u u u u ∂ r(u,v) = h∂ x(u,v),∂ y(u,v),∂ z(u,v)i. v v v v Explicit, implicit, parametric equations of surfaces Example p Find a parametric expression for the cone z = x2 +y2, and two tangent vectors. Solution: Use cylindrical coordinates: x = r cos(θ), y = r sin(θ), z = z. Parameters of the surface: u = r, v = θ. Then x(r,θ) = r cos(θ), y(r,θ) = r sin(θ), z(r,θ) = r. Using vector notation, a parametric equation of the cone is r(r,θ) = hr cos(θ),r sin(θ),ri. Two tangent vectors to the cone are ∂ r and ∂ r, r θ ∂ r = hcos(θ),sin(θ),1i, ∂ r = h−r sin(θ),r cos(θ),0i. r θ ⊳ Explicit, implicit, parametric equations of surfaces Example Find a parametric expression for the sphere x2 + y2 + z2 = R2, and two tangent vectors. Solution: Use spherical coordinates: x = ρcos(θ)sin(φ), y = ρsin(θ)sin(φ), z = ρcos(φ). Parameters of the surface: u = θ, v = φ. x = Rcos(θ)sin(φ), y = Rsin(θ)sin(φ), z = Rcos(φ). Using vector notation, a parametric equation of the cone is r(θ,φ) = R hcos(θ)sin(φ), sin(θ)sin(φ), cos(φ)i. Two tangent vectors to the paraboloid are ∂ r and ∂ r, θ φ ∂ r = R h−sin(θ)sin(φ), cos(θ)sin(φ), 0i, θ ∂φr = R hcos(θ)cos(φ), sin(θ)cos(φ), −sin(φ)i. ⊳
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