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Chapter 7 Eigenvalues and Eigenvectors 7.1 Eigenvalues and Eigenvectors 7.2 Diagonalization 7.1 Eigenvalues and Eigenvectors Eigenvalue problem: n If A is an nn matrix, do there exist nonzero vectors x in R such that Ax is a scalar multiple of x? Eigenvalue and eigenvector: Geometrical Interpretation A:an nn matrix :a scalar n x:a nonzero vector in R Eigenvalue Ax x Eigenvector 1/53 Ex 1: (Verifying eigenvalues and eigenvectors) 2 0 1 0 A x x 1 2 0 1 0 1 Eigenvalue 2 0 1 2 1 Ax 2 2x 1 1 0 1 0 0 0 Eigenvector Eigenvalue 2 0 0 0 0 Ax 1 (1)x 2 2 0 1 1 1 1 Eigenvector 2/53 Thm 7.1: (The eigenspace of A corresponding to ) If A is an nn matrix with an eigenvalue , then the set of all eigenvectors of together with the zero vector is a subspace of n R . This subspace is called the eigenspace of . Pf: x1 and x2 are eigenvectors corresponding to (i.e. Ax x , Ax x ) 1 1 2 2 (1) A(x x ) Ax Ax x x (x x ) 1 2 1 2 1 2 1 2 (i.e. x x is an eigenvector corresponding to λ) 1 2 (2) A(cx ) c(Ax ) c(x ) (cx ) 1 1 1 1 (i.e. cx is an eigenvector corresponding to ) 1 3/53
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