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PRECALCREVIEW:MODELINGwithFUNCTIONSI Modeling with Linear Functions • Basic Linear Function is y = mx + b, with slope m and y−intercept b. Alternate (point-slope) form y = y +m(x−x ), given one data point (x ,y ). 1 1 1 1 • Important Application is Data Fitting (linear regression): given x,y data, find the “best-fit” line for the data. Example: Columbia River Depth vs Flow Velocity Data (Problem 1.2.45) Problem 45 River Data Channel Flow Velocity as funciton of River Depth 1.6 1.4 1.2 1 Flow Velocity0.8 0.6 0.4 0.20 2 4 6 8 10 12 Depth in Feet Data value lists for x and y x = [ .7 2 2.6 3.3 4.6 5.9 7.3 8.6 9.9 10.6 11.2]; y = [1.55 1.11 1.42 1.39 1.39 1.14 .91 .59 .59 .41 .22]; 2 PRECALCREVIEW:MODELINGwithLINEARFUNCTIONS Modeling problem: how to find good m and b values for y = mx + b. Some possibilities: a) use first two data values: slope m = (y2 − y1)/(x2 − x1) ≈ −.3385. b) use first and last data values: slope m = (y −y )/(x −x )≈−.1267. 11 1 11 1 c) use all data values to find “best-fit” line: using calculus and Matlab m = −.1165, b = 1.681. Problem 45 River Data Fit Lines 2 1.5 1 0.5 0 −0.5 −1 −1.5 −2 −2.50 2 4 6 8 10 12 Estimated river velocity with 12 ft depth is ? 3 Math formulas for best-fit line slope and intercept: nPxy −Px Py Py −mPx i i i i i i m= P 2 P 2 , b= ; n x −( x) n i i Matlab instructions for previous graph x = [.7 2 2.6 3.3 4.6 5.9 7.3 8.6 9.9 10.6 11.2]; y = [1.55 1.11 1.42 1.39 1.39 1.14 .91 .59 .59 .41 .22]; p = polyfit( x, y, 1 ); m = p(1), b = p(2) m1 = (y(2)-y(1))/(x(2)-x(1)); m2 = (y(11)-y(1))/(x(11)-x(1)); plot(x,y,’*’,x,y(1)+m1*(x-x(1)),x,y(1)+m2*(x-x(1)),x,b+m*x) 4 PRECALCREVIEW:MODELINGwithFUNCTIONSCONT. Modeling with Periodic Functions • Basic Periodic Function is y = acos(bx) or y = acos(bx − c) with amplitude |a|, period 2π/b, and phase shift c/b; could also use y = acos(bx − c) + d or sin instead of cos. • Model Application: need to find good values for a, b, and maybe c, d. Example: some plotted data values 6 5 4 3 2 1 0 −1 −20 1 2 3 4 5 6 7 8 9 10 a?, b?, c?, d?.
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